PhpSettings.fromJson constructor

PhpSettings.fromJson(
  1. Map json_
)

Implementation

PhpSettings.fromJson(core.Map json_)
  : this(
      common: json_.containsKey('common')
          ? CommonLanguageSettings.fromJson(
              json_['common'] as core.Map<core.String, core.dynamic>,
            )
          : null,
      libraryPackage: json_['libraryPackage'] as core.String?,
    );